Question

"During a race, a dragster has an average acceleration of 39.8 m/s^2. If the dragster finishes the race in 4.20 seconds, how many meters does it travel? (Round your answer to the nearest whole number.

Do not include units in your answer)?

Answer 1

To calculate the distance a dragster travels with an average acceleration of 39.8 m/s² during a 4.20-second race, the kinematic equation is used, yielding a result of 351 meters when rounded to the nearest whole number.

Step-by-step explanation:

To find out how many meters a dragster travels during a race with an average acceleration of 39.8 m/s2 finishing in 4.20 seconds, we can use the kinematic equation for uniformly accelerated motion without initial velocity: distance = 0.5 × acceleration × time2. The dragster starts at rest and then accelerates, so the initial velocity is zero.

By plugging in the values:

distance = 0.5 × 39.8 m/s2 × (4.20 s)2

distance = 0.5 × 39.8 m/s2 × 17.64 s2

distance = 350.784 m

When rounded to the nearest whole number, the dragster travels 351 meters.