Question

"The top three teams in the AL East in 2018 were the Red Sox, the Yankees, and the Blue Jays. The Yankees won 17 less games than the Blue Jays. The Red Sox won 9 more than twice the number of games that the Blue Jays did. The three teams combined for 292 wins. How many games did the Red Sox Win?

72
91
103
159"

Answer 1

The Red Sox won 125 games.

Step-by-step explanation:

To determine the number of games the Red Sox won, we can start by assigning variables to the number of games won by each team. Let's say the Red Sox won x games, the Yankees won 17 less than the Blue Jays, so they won x - 17 games, and the Blue Jays won y games. We're also given that the Red Sox won 9 more than twice the number of games the Blue Jays did, so we can write the equation 2y + 9 = x.

Since the three teams combined for 292 wins, we can set up another equation: x + (x - 17) + y = 292. Simplifying this equation, we have 2x + y - 17 = 292.

To solve these two equations, we can substitute 2y + 9 for x in the second equation. We get 2(2y + 9) + y - 17 = 292. Simplifying this equation, we have 5y + 1 = 292. Solving for y, we find y = 58. Substituting y = 58 back into the equation 2y + 9 = x, we find x = 125.

Therefore, the Red Sox won 125 games.