Question

"What would the coefficient of friction be between the crate and the ground if there is a frictional force of 5N between the crate and the floor, and a force of 50N at 25° above the horizontal is pushing diagonally downward on the crate?

A. 0.43
B. 0.03
C. 0.11
D. 0.00

Select the correct option that represents the coefficient of friction in this scenario."

Answer 1

The coefficient of friction between the crate and the ground in this scenario is approximately 0.11.

Step-by-step explanation:

The coefficient of friction can be determined by using the equation of static friction Fs = μsN, where μs is the coefficient of static friction and N is the normal force.

In this scenario, a force of 50N at 25° above the horizontal is pushing diagonally downward on the crate. We can resolve this force into its components to find the normal force and the force parallel to the floor.

The component of the force parallel to the floor is 50N * cos(25°) = 45.72N. Therefore, the coefficient of friction is the frictional force (5N) divided by the force parallel to the floor (45.72N): μ = 5N / 45.72N ≈ 0.11.