Final answer:
To find the approximate time it will take for the sample to have approximately 65,459 bacteria, we can solve the equation A = 256e^(1.386t) = 65,459 for t. The approximate time is 4.42 hours.
Step-by-step explanation:
To find the approximate time it will take for the sample to have approximately 65,459 bacteria, we can set up the equation A = 256e^(1.386t) equal to 65,459 and solve for t.
65,459 = 256e^(1.386t)
Divide both sides by 256:
e^(1.386t) = 65,459 / 256
Take the natural logarithm of both sides:
ln(e^(1.386t)) = ln(65,459 / 256)
Use the property of logarithms to bring the exponent down:
1.386t * ln(e) = ln(65,459 / 256)
ln(e) is equal to 1, so we can simplify:
1.386t = ln(65,459 / 256)
Divide both sides by 1.386 to solve for t:
t = ln(65,459 / 256) / 1.386
Using a calculator, we find that t is approximately 4.42 hours. Therefore, in approximately 4.42 hours, there will be approximately 65,459 bacteria in the sample.