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A cave explorer travels 18.0 meters eastward, and then 8.50 meters northward. Find the resultant displacement for the explorer.

Please calculate and provide the magnitude and direction of the resultant displacement.

User MarkXA
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Final answer:

The cave explorer's resultant displacement is approximately 19.9 meters at an angle of 25.2° north of east.

Step-by-step explanation:

To find the resultant displacement for the cave explorer who travels 18.0 meters eastward and then 8.50 meters northward, we can use the Pythagorean theorem since this movement creates a right-angle triangle with the two paths as the legs and the resultant displacement as the hypotenuse. First, we calculate the magnitude of the resultant displacement:

  • Magnitude (√): √(18.0² + 8.50²) = √(324 + 72.25) = √396.25 = 19.9 meters

To find the direction of the resultant displacement, we need the angle θ with respect to east (assuming east as the 0° direction). This is done by taking the inverse tangent of the northward displacement over the eastward displacement:

  • Direction (θ): tan-1(8.50/18.0) = tan-1(0.4722) ≈ 25.2°

The direction is 25.2° north of east. So, the explorer's resultant displacement is approximately 19.9 meters at 25.2° north of east.

User Filaton
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