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"Quadrilateral JKLM is a rhombus. The diagonals intersect at N. If angle KNJ equals 8x + 6, find the value of x."

User Ryohei
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1 Answer

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Final answer:

The value of x in angle KNJ of a rhombus quadrilateral JKLM can be found by setting the angle equal to 90 degrees.

Step-by-step explanation:

Since quadrilateral JKLM is a rhombus, the diagonals are perpendicular to each other and bisect each other at point N.

We are given that angle KNJ is equal to 8x + 6.

Since the diagonals of a rhombus are perpendicular, angle KNJ is equal to angle KJM. Therefore, 8x + 6 = 90 degrees.

Solving for x, we subtract 6 from both sides of the equation and then divide by 8: 8x = 84, x = 10.5.

Therefore, the value of x is 10.5.

User JoseCarlosPB
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