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Write the equation of the line that has a slope of 1/3 and goes through point (15, -1).​

User Pseudosudo
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Final answer:

The equation of the line with a slope of 1/3 that passes through the point (15, -1) is y = (1/3)x - 5.

Step-by-step explanation:

To write the equation of the line that has a slope of 1/3 and goes through the point (15, -1), we can use the point-slope form of a line's equation: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line. Plugging the given point and slope into this formula, we get:



y - (-1) = (1/3)(x - 15)



Simplifying, we add 1 to both sides:



y = (1/3)x - 5



This is the slope-intercept form of the equation, where the y-intercept is -5. The equation y = (1/3)x - 5 represents the line with a slope of 1/3 passing through the point (15, -1).

User Nima Rostami
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