Question

Kyle wins a coupon for $8 off the lunch special for each of 3 days. He pays $60 for his 3 lunch specials. Write and solve an equation to find the original price p for one lunch special.

A. 3p - $24 = $60; p = $28
B. 3p + $24 = $60; p = $12
C. 3p - $8 = $60; p = $24
D. 3p + $8 = $60; p = $16

Answer 1

The original price p for one lunch special is $28.

Step-by-step explanation:

To find the original price p for one lunch special, we can set up the equation:

3p - $24 = $60

Next, we can solve for p by isolating it on one side of the equation:

3p = $60 + $24

3p = $84

p = $84 ÷ 3

p = $28

Therefore, the original price p for one lunch special is $28, which means each lunch special originally costs $28 before the coupon discount.