Final answer:
The resistance of the lightbulb is approximately 5.24 kilohms.
Step-by-step explanation:
To find the resistance of the lightbulb, we can use Ohm's Law, which states that resistance is equal to voltage divided by current: R = V/I. Given that the current is 0.021 amps and the voltage is 110 volts, we can substitute these values into the formula: R = 110 / 0.021 = 5238.10 ohms (or approximately 5.24 kilohms). Therefore, the resistance of the lightbulb is approximately 5.24 kilohms.