Question

A sphere of radius 50 mm and mass 1 kg falling vertically through air of density 1.2 kg/m^3 attains a steady velocity of 11.0 m/s. If the above equation is applied to it, what is the value of k in this case?

a) 2.21
b) 4.42
c) 1.11
d) 0.55

Answer 1

The value of k in the given equation is approximately 0.55.

Step-by-step explanation:

The equation provided in the question is likely the equation for the drag force experienced by an object falling through a fluid. The equation is Fd = kAv2, where Fd is the drag force, k is a constant, A is the cross-sectional area of the object, and v is the velocity of the object.

Given that the sphere has attained a steady velocity of 11.0 m/s and the air density is 1.2 kg/m3, we can solve for k.

Let's substitute the known values into the equation: 1 kg * 9.8 m/s2 = k * (π * (50 mm)2) * (11.0 m/s)2.

After solving for k, we find that the value of k is approximately 0.55.