Final answer:
The javelin travels approximately 8.28 meters vertically.
Step-by-step explanation:
In this case, the javelin is thrown at a speed of 18 m/s at an angle of 30° above the horizontal. To find the vertical distance traveled by the javelin, we need to calculate the vertical component of its initial velocity.
The vertical component of the initial velocity can be found using the equation:
Vertical Component of Initial Velocity (Voy) = Initial Velocity (V) * sin(θ)
Where V is the initial velocity (18 m/s) and θ is the angle (30°).
Plugging in the values, we get:
Voy = 18 m/s * sin(30°)
Voy ≈ 9 m/s
The total flight time can be calculated using the equation:
Total Flight Time (t) = 2 * (Vertical Component of Initial Velocity (Voy) / Acceleration due to Gravity (g))
Where g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the values, we get:
t = 2 * (9 m/s / 9.8 m/s^2)
t ≈ 1.84 seconds
The vertical distance traveled by the javelin can then be calculated using the equation:
Vertical Distance Traveled (dy) = Vertical Component of Initial Velocity (Voy) * Time taken to reach Maximum Height (t/2)
Plugging in the values, we get:
dy = 9 m/s * 0.92 seconds
dy ≈ 8.28 meters
Therefore, the javelin travels approximately 8.28 meters vertically.