Final answer:
To find the temperature of 2.15 moles of butane with a volume of 135 L and a pressure of 2.4 atm, we can use the ideal gas law equation PV = nRT. Plugging in the given values and solving for T, we find that the temperature is approximately 180.2 K.
Step-by-step explanation:
To find the temperature of 2.15 moles of butane, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
Let's plug in the given values: P = 2.4 atm, V = 135 L, n = 2.15 moles. The gas constant R is 0.0821 L*atm/(mol*K). Rearranging the equation, we get T = (PV)/(nR).
Substituting the values, we have T = (2.4 atm * 135 L) / (2.15 mol * 0.0821 L*atm/(mol*K)). Solving this equation, we find that T is approximately 180.2 K.