Final answer:
The 150th term of the arithmetic sequence (16, 12, 8, 4) with a common difference of -4 is -580, which is calculated using the nth term formula for an arithmetic sequence.
Step-by-step explanation:
The first 4 numbers of an arithmetic sequence are given: 16, 12, 8, 4. In an arithmetic sequence, each term is equal to the previous term plus a constant difference. In this case, the difference is -4 (since 12 - 16 = -4, 8 - 12 = -4, and so on).
To find the value of the 150th term of the sequence, we use the formula for the nth term of an arithmetic sequence:
Tn = a + (n - 1)d, where:
- Tn is the nth term of the sequence,
- a is the first term of the sequence,
- n is the term number,
- d is the common difference.
Plugging in the given values:
T150 = 16 + (150 - 1)(-4)
T150 = 16 + (149)(-4)
T150 = 16 - 596
T150 = -580
Therefore, the value of the 150th term of the sequence is -580, which is not listed in the options provided. It seems there might be an error in the provided choices.