Question

In a photography studio, you've previously created a function in Part B to represent the relationship between the number of pictures taken and the cost of a photography package. Now, you're considering a package of 60 pictures. Can you anticipate the price for this package? Please justify your answer algebraically using the function you developed in Part B, and plot the corresponding point on the scatterplot you created in Part A

Answer 1

To anticipate the price of a photography package with 60 pictures, we can use the function we developed in Part B. By finding the values of m and b, substituting x = 60 into the equation, we can calculate the price of the package.

Step-by-step explanation:

To anticipate the price of a photography package with 60 pictures, we can use the function we developed in Part B. Let's say the function is represented as y = mx + b, where y is the cost of the package and x is the number of pictures taken. First, we need to find the values of m and b. We can do this by using two points on the scatter plot from Part A. Once we have the values of m and b, we can substitute x = 60 into the equation to find the price of the package.

1. Use the two points from the scatter plot to form a system of equations using the equation y = mx + b. For example, if the points are (x1, y1) and (x2, y2), you will have two equations: y1 = m*x1 + b and y2 = m*x2 + b.
2. Solve the system of equations to find the values of m and b.
3. Substitute x = 60 into the equation y = mx + b and calculate the price of the package.

For example, if the system of equations gives you the values m = 2 and b = 50, then the equation representing the relationship between the number of pictures and the cost of the package is y = 2x + 50. Substituting x = 60 into the equation, we get y = 2*60 + 50 = 170. Therefore, the price for a package of 60 pictures would be $170.