151k views
1 vote
A square with sides of length 8 units is positioned on a graph with its lower-left-hand corner at the origin (0,0). This square is then translated 5 units up and 7 units to the left. What are the coordinates of the upper-right-hand corner of the square after this translation? Please provide an explanation for your answer

User Optixx
by
7.7k points

1 Answer

5 votes

Final answer:

To find the new position of the upper-right-hand corner after the square is translated 5 units up and 7 units to the left, subtract 7 from the x-coordinate and add 5 to the y-coordinate of the original corner, resulting in the new coordinates being (1, 13).

Step-by-step explanation:

The question involves finding the coordinates of the upper-right-hand corner of a square after it undergoes a translation.

Initially, the square has sides of length 8 units and its lower-left-hand corner at the origin (0,0).

After a translation of 5 units up and 7 units to the left, the new position of the square can be determined.

Before translation, the upper-right-hand corner would have been at (8,8), as it is 8 units to the right and 8 units up from the origin.

To find the new coordinates after the translation, we subtract 7 units from the x-coordinate and add 5 units to the y-coordinate (since moving up increases the y-value and moving left decreases the x-value):

Therefore, the coordinates of the upper-right-hand corner of the square after the translation are (1, 13).

User Thedreamsaver
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories