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A square with sides of length 8 units is positioned on a graph with its lower-left-hand corner at the origin (0,0). This square is then translated 5 units up and 7 units to the left. What are the coordinates of the upper-right-hand corner of the square after this translation? Please provide an explanation for your answer

User Optixx
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Final answer:

To find the new position of the upper-right-hand corner after the square is translated 5 units up and 7 units to the left, subtract 7 from the x-coordinate and add 5 to the y-coordinate of the original corner, resulting in the new coordinates being (1, 13).

Step-by-step explanation:

The question involves finding the coordinates of the upper-right-hand corner of a square after it undergoes a translation.

Initially, the square has sides of length 8 units and its lower-left-hand corner at the origin (0,0).

After a translation of 5 units up and 7 units to the left, the new position of the square can be determined.

Before translation, the upper-right-hand corner would have been at (8,8), as it is 8 units to the right and 8 units up from the origin.

To find the new coordinates after the translation, we subtract 7 units from the x-coordinate and add 5 units to the y-coordinate (since moving up increases the y-value and moving left decreases the x-value):

Therefore, the coordinates of the upper-right-hand corner of the square after the translation are (1, 13).

User Thedreamsaver
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