Final answer:
To find the stealth bomber's acceleration, convert the velocities from km/h to m/s and divide the change in velocity by time. After conversion and calculation, the stealth bomber's acceleration is approximately 0.473 m/s², which is closest to answer choice C.
Step-by-step explanation:
To calculate the stealth bomber's acceleration, we need to use the formula for acceleration , which is the change in velocity (Δv) divided by the change in time (Δt). The bomber's initial velocity is 600 km/h, and its final velocity is 1,010 km/h. Since acceleration is usually expressed in meters per second squared (m/s²), we will first convert the velocities into meters per second.
1 km/h = 1,000 m / 3,600 s = 0.27778 m/s
Initial velocity in m/s: 600 km/h * 0.27778 m/s per km/h = 166.67 m/s
Final velocity in m/s: 1,010 km/h * 0.27778 m/s per km/h = 280.28 m/s
The change in velocity: Δv = 280.28 m/s - 166.67 m/s = 113.61 m/s
The time is 4 minutes, which is 4 * 60 seconds = 240 seconds.
Acceleration () = Δv / Δt = 113.61 m/s / 240 s = 0.473375 m/s²
The correct answer closest to this calculated value is C. 0.473 m/s².