Question

If an object is dropped from a tall building with an average acceleration of 9.8 m/s², how long will it take before it reaches a speed of 51.0 m/s?

A) 499.8 seconds
B) 0.19 seconds
C) 5.2 seconds
D) 10 seconds

Answer 1

The object will take 5.2 seconds to reach a speed of 51.0 m/s.

Step-by-step explanation:

To determine how long it will take for the object to reach a speed of 51.0 m/s, we can use the equation:

v = u + at

where v is the final velocity, u is the initial velocity (which is 0 m/s in this case), a is the acceleration (which is 9.8 m/s²), and t is the time. Rearranging the equation to solve for t, we have:

t = (v - u) / a

Substituting the values, we get:

t = (51.0 - 0) / 9.8 = 5.2 seconds