Final answer:
The net force on object X in the given scenario is D. 4N
Step-by-step explanation:
To determine the net force on object X, we need to add up all the forces acting on it. The forces acting on object X are given as:
Force 1: 10N (applied by the first object)
Force 2: 6N (applied by the second object)
Force 3: 4N (applied by the third object)
We can add these forces vectorially by drawing a diagram of the situation and adding the forces as vectors. Let’s assume that the objects are placed at positions (0, 0), (3, 0), and (2, 4) meters away from the origin, respectively.
Using the Pythagorean theorem, we can calculate the magnitude of each force as follows:
Force 1: 10N (cos(θ1) = 1, sin(θ1) = 0, where θ1 is the angle between the force and the x-axis)
Force 2: 6N (cos(θ2) = 0.5, sin(θ2) = 0.5, where θ2 is the angle between the force and the x-axis)
Force 3: 4N (cos(θ3) = 0.7, sin(θ3) = 0.7, where θ3 is the angle between the force and the x-axis)
Now, let’s add these forces vectorially:
Net force = Force 1 + Force 2 + Force 3 = 10N + 6N + 4N = 4N
Since the net force is 20N, the object will accelerate in the direction of the net force. However, we need to consider other factors such as friction and air resistance to determine the actual acceleration of the object.