Question

You get called to help your friend move. You are asked to move this 125 kg box from the front door into the moving truck, which has a ramp attached to it. You could not move the box at all, even when you pushed your hardest.

What is the force (F) acting on the box if the coefficient of friction between the box and the driveway is 0.5?

A) 612.5 N
B) 625 N
C) 6250 N
D) 61250 N

Answer 1

The force acting on the box is 612.5 N.

Step-by-step explanation:

To determine the force acting on the box, we need to calculate the maximum force of static friction. The formula for static friction is fs = µs * N, where µs is the coefficient of friction and N is the normal force acting on the box. In this case, the normal force is equal to the weight of the box, which is given by N = m * g, where m is the mass of the box and g is the acceleration due to gravity. With the given information, we can find the force (F) acting on the box:

1. Calculate the normal force: N = m * g = 125 kg * 9.8 m/s² = 1225 N
2. Calculate the maximum force of static friction: fs = µs * N = 0.5 * 1225 N = 612.5 N

Therefore, the force acting on the box is 612.5 N.