Question

What is the equation of the line that passes through the point (4, 11) and is perpendicular to the line with the equation y = -1 + 8?aWhat is the equation of the line that passes through the point (4, 11) and is perpendicular to the line with the equation y = -1 + 8?

A) y = 1 + 7
B) y = 1 - 15
C) y = -1 + 14
D) y = -1 + 7

Answer 1

The equation of the line that passes through the point (4, 11) and is perpendicular to the line y = -1 + 8 is y = -1/8x + 15/2.

Step-by-step explanation:

To find the equation of a line that is perpendicular to another line, we need to find the negative reciprocal of the slope of the given line. The given line has a slope of 8, so the perpendicular line will have a slope of -1/8.

We can use the point-slope form of a line to find the equation. The point-slope form is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Since the line passes through the point (4, 11), the equation of the perpendicular line is y - 11 = -1/8(x - 4). Simplifying this equation gives us y = -1/8x + 15/2.