92.6k views
5 votes
Madeline invested $960 in an account paying an interest rate of 3-5% compounded daily. Assuming no deposits or withdrawals are made, how long would it take, to the nearest year, for the value of the account to reach $1,250?

A) 6 years
B) 7 years
C) 8 years
D) 9 years
E) 10 years

1 Answer

1 vote

Final answer:

By using the formula for compound interest and solving for the time variable, we find that it will take approximately 8 years for Madeline's investment to grow to $1,250, with the closest answer being 8 years (option C).

Step-by-step explanation:

To determine how long it will take for Madeline's investment to grow to $1,250 with an interest rate compounded daily, we can use the formula for compound interest:

A = P(1 + \frac{r}{n})^{nt}

Where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested for in years.

We need to solve for t, the time in years, and we have the following information:

  • A = $1,250
  • P = $960
  • r = 3.5% or 0.035 (as a decimal)
  • n = 365 (since the interest is compounded daily)

Substituting these values into the formula, we get:

$1,250 = $960(1 + \frac{0.035}{365})^{365t}

Now solving for t, we find:

$1,250 / $960 = (1 + \frac{0.035}{365})^{365t}

1.30208333 = (1 + 0.00009589041)^{365t}

Using logarithms to solve for t, we have:

log(1.30208333) = log((1 + 0.00009589041)^{365t})

log(1.30208333) = 365t * log(1 + 0.00009589041)

t = \frac{log(1.30208333)}{365 * log(1 + 0.00009589041)}

After calculating, we find that t is approximately 8.04 years.

Therefore, the closest answer to the nearest year is 8 years, which is option C.

User RoundPi
by
8.4k points