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What is the equation for a parabola that passes through the point (2, -18) and has x-intercepts at (-1,0) and (4,0)?

A) y = 3x^2 - 8x - 18
B) y = -3x^2 + 8x - 18
C) y = -3x^2 - 8x + 18
D) y = 3x^2 + 8x + 18

User Uzi
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1 Answer

3 votes

Final answer:

The correct equation for the parabola is not listed in the provided options, but the process involves using the factored form and the point (2, -18) to find the correct equation. The closest answer is option A, which suggests there may be an error in the question or options.

Step-by-step explanation:

The equation for a parabola that passes through the point (2, -18) with x-intercepts at (-1,0) and (4,0) can be determined by using the factored form of a quadratic equation, y = a(x - r)(x - s), where r and s are the roots of the parabola.

In this case, the roots are x = -1 and x = 4. Therefore, the equation starts as y = a(x + 1)(x - 4).

Now we need to find the value of 'a' that will make the parabola pass through the point (2, -18). Substituting the point into the equation gives us -18 = a(2 + 1)(2 - 4) which simplifies to -18 = a(3)(-2), so a = 3. Thus, our equation now becomes y = 3(x + 1)(x - 4).

To find the standard form of the equation, we expand the factored form: y = 3(x^2 - 4x + x - 4), which simplifies to y = 3(x^2 - 3x - 4). Multiplying each term by 3, we get the equation y = 3x^2 - 9x - 12. Comparing this with the given options, none of them is correct but option A is the closest to the correct form. It seems there might be an error in the question or in the provided options.

User Benjamin Penney
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