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Shreya's school is selling tickets to the annual dance competition. On the first day of ticket sales, the school sold 2 adult tickets and 8 child tickets for a total of $62. The school took in $79 on the second day by selling 5 adult tickets and 1 child ticket. Find the price of an adult ticket and the price of a child ticket.

A. Adult ticket price: $6, Child ticket price: $4
B. Adult ticket price: $10, Child ticket price: $5
C. Adult ticket price: $8, Child ticket price: $2
D. Adult ticket price: $7, Child ticket price: $3

1 Answer

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Final answer:

After setting up and solving a system of linear equations based on the given information, the price of an adult ticket is found to be $15, while the price of a child ticket is $4.

Step-by-step explanation:

To determine the price of adult and child tickets sold by Shreya's school, we need to set up a system of linear equations based on the information provided:

Let A be the price of an adult ticket, and C be the price of a child ticket.

From the first day of sales: 2A + 8C = $62

From the second day of sales: 5A + 1C = $79

Solving this system of equations, we multiply the second equation by 8 to eliminate C:

  • 2A + 8C = $62
  • 40A + 8C = $632

Subtracting the first equation from the modified second equation:

  • 40A - 2A = $632 - $62
  • 38A = $570
  • A = $15

Substituting A into the first equation:

  • 2($15) + 8C = $62
  • 30 + 8C = $62
  • 8C = $32
  • C = $4

The final answer in 2 lines: Adult ticket price is $15; Child ticket price is $4.

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