Question

What is the force on a 1750 kg elevator that is free falling at 9.8 m/s^2?

A. 9.8 N
B. 17,150 N
C. 0 N
D. 1,750 N

Answer 1

The force on a free-falling elevator with a mass of 1750 kg can be calculated using Newton's second law. The force is 17,150 N.

Step-by-step explanation:

The force on a free-falling elevator can be calculated using Newton's second law, which states that force equals mass times acceleration.

Given:

• Mass of the elevator (m): 1750 kg
• Acceleration due to gravity (g): 9.8 m/s²

Force = mass × acceleration

Force = 1750 kg × 9.8 m/s²

Force = 17,150 N

Therefore, the correct answer is Option B. 17,150 N.