Final answer:
The student's question seems to contain a mistake as it mixes up lithium bromide with sodium iodide. For a correct scenario, where a solution is 5.00% lithium bromide by mass, there would be 6.25 grams of lithium bromide in 125.0 grams of solution, using the mass percentage calculation.
Step-by-step explanation:
The student’s question concerns the calculation of the amount of a specific solute, lithium bromide, in a given mass percentage solution. However, there seems to be a misunderstanding in the question. The student is asking for the amount of lithium bromide in a solution that is described as being 5.00% sodium iodide by mass. Since the solutes are different (sodium iodide versus lithium bromide), without additional information about the lithium bromide, the question cannot be directly answered. Instead, I will provide an example of how to calculate the mass of a solute in a solution based on a given mass percentage.
Example Calculation of Mass of Solute in a Mass Percentage Solution
Suppose you have a solution that is 5.00% lithium bromide by mass. If the total mass of the solution is 125.0 grams, the mass of lithium bromide can be calculated as follows:
Mass of lithium bromide = (Mass percentage of LiBr / 100) × Total mass of the solution
= (5.00 / 100) × 125.0 g
= 0.05 × 125.0 g
= 6.25 g
Therefore, if the solution were 5.00% lithium bromide by mass, there would be 6.25 grams of lithium bromide in 125.0 grams of solution.