Question

A solution is formed by dissolving 29.2 grams of sodium chloride (NaCl) in 3.0 liters of solution. The molar mass of NaCl is 58.5 g/mol.What is the molarity of the solution?

Answer 1

0.17M. Option B is correct

Explanations:

The formula calculating the molarity of a solution is given as:

`M=(n)/(v)`

where:

n is the moles of sodium chloride

v is the volume of the solution

Given the following parameters;

The volume of the solution = 3.0L

Determine the moles of NaCl

`\begin{gathered} \text{Moles of NaCl=}\frac{Mass}{Molar\text{ mass}} \\ \text{Moles of NaCl=}(29.2g)/(23+35) \\ \text{Moles of NaCl=}(29.2g)/(58.5) \\ \text{Moles of NaCl=}0.499\text{moles} \end{gathered}`

Calculate the required molarity

`\begin{gathered} \text{Molarity}=\frac{0.499\text{moles}}{3.0L} \\ Molarity\approx0.17M \end{gathered}`

Hence the molarity of the solution is 0.17M