Final answer:
To find the amount of lithium hydroxide produced when 20.1 grams of water react completely, we can convert the grams of water to moles and use the stoichiometric ratio from the balanced equation.
Step-by-step explanation:
In this reaction, 20.1 grams of water is given and we need to find the amount of lithium hydroxide (LiOH) produced. First, we convert the grams of water to moles by dividing by the molar mass of water, which is 18 g/mol. So, 20.1 g of water is equal to 1.117 moles.
According to the balanced equation, 2 moles of water react completely to produce 2 moles of LiOH. Therefore, we can conclude that 1.117 moles of water will produce 1.117 moles of LiOH.