Final answer:
Calculating using the work-energy theorem, the work done on a 10 kg mass given a speed change from 4 m/s to 6 m/s is 100 Joules.
Step-by-step explanation:
The work done on an object can be calculated using the work-energy theorem, which states that the net work done on a system equals the change in kinetic energy. For a mass of 10 kg with an increase in speed from 4 m/s to 6 m/s, this change in kinetic energy can be computed using the given formula:
W = 0.5 × mass × (final velocity² - initial velocity²)
Plugging in the values, we get:
W = 0.5 × 10 kg × ((6 m/s)² - (4 m/s)²)
W = 0.5 × 10 kg × (36 m²/s² - 16 m²/s²)
W = 0.5 × 10 kg × 20 m²/s²
W = 5 kg × 20 m²/s²
W = 100 kg·m²/s²
W = 100 Joules
Hence, the work done by the force, in SI units which are measured in Joules (J), is 100 J.