Question

What is the range of y = x2 - 8x + 4?

A) y s 12
B) x y 12
C) y^2-12
D) x^2 -12

Answer 1

The range of the equation y = x^2 - 8x + 4 is y = 4.

Step-by-step explanation:

The range of the quadratic equation y = x2 - 8x + 4 can be determined by finding the vertex of the parabola represented by this equation. The x-coordinate of the vertex is given by x = -b/2a, where a = 1, b = -8, and c = 4. Plugging these values into the formula, we get x = -(-8)/2(1) = 4. The y-coordinate of the vertex is then found by substituting this value of x back into the equation, giving us y = (4)^2 - 8(4) + 4 = 4.

Therefore, the range of the equation is y = 4.