Final answer:
The second smallest of three consecutive even numbers whose sum is 42 is found to be 14 by setting up an equation and solving for the smallest number first.
Step-by-step explanation:
To find the second smallest of three consecutive even numbers whose sum is 42, we can set up a simple equation. Let the smallest number be x, the second number will then be x + 2, and the largest number will be x + 4. The equation based on the given sum is:
x + (x + 2) + (x + 4) = 42.
Simplifying the equation, we get:
3x + 6 = 42
Subtract 6 from both sides:
3x = 36
Then divide by 3:
x = 12
Therefore, the second smallest number is:
x + 2 = 14.
The second smallest of these three consecutive even numbers is 14.