106k views
0 votes
"Evaluate the function for x=-1, 0, 4 for the function g(x)=3x^2+1."

User Bets
by
7.8k points

1 Answer

3 votes

Final answer:

The function g(x) = 3x^2 + 1 evaluates to 4 when x = -1, to 1 when x = 0, and to 49 when x = 4.

Step-by-step explanation:

To evaluate the function g(x) = 3x^2 + 1 for x = -1, x = 0, and x = 4, we need to substitute each value of x into the function and simplify.

  • For x = -1:
    g(-1) = 3(-1)^2 + 1 = 3(1) + 1 = 3 + 1 = 4
  • For x = 0:
    g(0) = 3(0)^2 + 1 = 3(0) + 1 = 0 + 1 = 1
  • For x = 4:
    g(4) = 3(4)^2 + 1 = 3(16) + 1 = 48 + 1 = 49

Therefore, the values of the function g(x) evaluated at x = -1, x = 0, and x = 4 are 4, 1, and 49, respectively.

User Amandeep Grewal
by
8.0k points