Final answer:
The scenario described does not fit into either a binomial setting or a geometric setting. The expected number of eggs Natasha's father would have to open before finding one containing a piece of candy is 3. The probability of finding the first piece of candy in the second Easter egg is 0.221, or 22.1%.
Step-by-step explanation:
(A) The scenario described does not fit into either a binomial setting or a geometric setting. In a binomial setting, there are a fixed number of trials with two possible outcomes, and in a geometric setting, each trial has a probability of success and the goal is to find the probability of achieving the first success after a certain number of trials. However, the scenario described does not fit into either of these frameworks.
(B) To find the expected number of eggs Natasha's father would have to open before finding one containing a piece of candy, we can use the concept of expected value. The expected value is calculated by multiplying each possible outcome by its probability and summing them up. In this case, since the probability of finding a piece of candy is 1 - 0.67 = 0.33, the expected number of eggs would be 1/0.33 = 3.03, which can be rounded to 3.
(C) The probability of finding the first piece of candy in the second Easter egg can be calculated by finding the probability of not finding a piece of candy in the first egg (0.67) and then finding a piece of candy in the second egg (0.33). Therefore, the probability is 0.67 * 0.33 = 0.221, or 22.1%.