Final answer:
The probability that the Camarillo basketball player makes all of her first four free throws and then misses her fifth attempt this season is approximately 0.08192.
Step-by-step explanation:
To find the probability that the Camarillo basketball player makes all of her first four free throws and then misses her fifth attempt, we multiply the probabilities of each individual event together. The probability of her making a free throw is 1 - P(missing a free throw), which is 1 - (1/4) = 3/4. So, the probability of making all four free throws is (3/4)^4. The probability of missing the fifth attempt is 1/4. Multiplying these probabilities together, we get (3/4)^4 * 1/4 = 81/1024, which is approximately 0.0791. Therefore, the correct option is b) 0.08192.