Final answer:
When 4.50 grams of CuSO4·5H2O are heated strongly to drive off all of the water of hydration, the mass of the remaining compound (CuSO4) after heating will be 0.018 grams.
Step-by-step explanation:
When CuSO4·5H2O is heated strongly, all the water of hydration is driven off. This means that the CuSO4 no longer contains any water molecules. To calculate the mass of the remaining compound after heating, we need to subtract the mass of the water that was driven off from the initial mass of CuSO4·5H2O.
The molar mass of CuSO4·5H2O can be calculated by adding the molar masses of the individual atoms:
- Cu: 63.55 g/mol
- S: 32.07 g/mol
- O: 16.00 g/mol (x4, because there are four oxygen atoms)
- H: 1.01 g/mol (x10, because there are ten hydrogen atoms)
Molar mass of CuSO4·5H2O = 63.55 + 32.07 + (16.00 x 4) + (1.01 x 10) = 249.68 g/mol
Now we can calculate the mass of CuSO4·5H2O using its molar mass:
Mass of CuSO4·5H2O = 4.50 g / 249.68 g/mol = 0.018 g/mol
Since all the water of hydration is driven off, the mass of the remaining compound (CuSO4) after heating will be the same as the mass of CuSO4·5H2O: 0.018 g/mol.