Question

"A 3.9-newton force is applied to the right on a 0.22-kilogram copper block sliding to the right on a horizontal steel table.

1. Determine the weight of the block.
Weight = ?
2. Calculate the magnitude of the force of friction acting on the moving block.
Force of Friction = ?
3. Determine the magnitude of the net force acting on the moving block.
Net Force = ?"

If you need assistance with these physics problems, feel free to ask for help with each part of the question.

Answer 1

The weight of the block is 2.156 N, the force of friction is 0.4312 N, and the net force is 3.4688 N.

Step-by-step explanation:

1. To determine the weight of the block, we can use the formula Weight = mass * acceleration due to gravity. Since the mass is given as 0.22 kilograms, and the acceleration due to gravity is approximately 9.8 meters per second squared, we can calculate the weight as:

Weight = 0.22 kg * 9.8 m/s² = 2.156 N

2. The magnitude of the force of friction can be found using the equation Frictional Force = coefficient of friction * normal force. Since the normal force is equal to the weight of the block (2.156 N), and the coefficient of friction is given as 0.20, we can calculate the force of friction as:

Force of Friction = 0.20 * 2.156 N = 0.4312 N

3. The net force acting on the moving block can be determined using the equation Net Force = Applied Force - Force of Friction. Since the applied force is given as 3.9 N and the force of friction is 0.4312 N, we can calculate the net force as:

Net Force = 3.9 N - 0.4312 N = 3.4688 N