Final answer:
To find the number of moles of fluorine gas in a 2.75 L container at 27.0 °C and 785 atm, the Ideal Gas Law is used, showing the container holds approximately 91.5 moles of fluorine gas.
Step-by-step explanation:
The subject of the question is Chemistry, and it pertains to high school grade level. To calculate the number of moles of fluorine gas contained in a 2.75 L container at 27.0 °C (which is 300.15 K) and 785 atm, we can use the Ideal Gas Law, which is PV = nRT. In this equation, P is pressure in atm, V is volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/K·mol), and T is the temperature in Kelvin.
First, we have to convert the temperature from Celsius to Kelvin by adding 273.15 to the Celsius temperature. Then we plug the values into the Ideal Gas Law:
P = 785 atm
V = 2.75 L
R = 0.0821 L·atm/K·mol
T = 27.0 °C + 273.15 = 300.15 K
n = PV / RT
n = (785 atm × 2.75 L) / (0.0821 L·atm/K·mol × 300.15 K)
n = 91.5 moles (rounded to three significant figures)
Therefore, the container holds approximately 91.5 moles of fluorine gas.