Question

У = 3x^2 + бх – 5

Axis of symmetry is:
Option 1: x = -б/6
Option 2: x = б/6
Option 3: x = -б/3
Option 4: x = б/3

Answer 1

The axis of symmetry for the quadratic equation y = 3x^2 + бx – 5 is found using the formula x = -b/2a. For the given equation, the axis of symmetry is x = -б/6.

Step-by-step explanation:

The question is asking to find the axis of symmetry for the quadratic equation у = 3x2 + бх – 5. To find the axis of symmetry for a quadratic equation in the form of ax2 + bx + c, you can use the formula x = -b/2a. Applying this formula to the given equation:

• a = 3
• b = б

We get the axis of symmetry as x = -б/(2 × 3), which simplifies to x = -б/6. Therefore, the correct answer is Option 1: x = -б/6.