Final answer:
The molarity of 0.26 moles of H2SO4 dissolved in 300 ml of solution is calculated by dividing the moles by the volume in liters, resulting in a molarity of 0.867 M.
Step-by-step explanation:
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In the case of 0.26 moles of H2SO4 dissolved in 300 ml (or 0.300 liters) of solution, the molarity can be calculated using the formula Molarity = moles of solute / liters of solution.
The calculation is: Molarity = 0.26 moles / 0.300 liters
Therefore, the molarity of the H2SO4 solution is 0.867 M.The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, we have 0.26 mol of H2SO4 dissolved in 300 mL of solution. To calculate the molarity, we need to convert the volume from milliliters to liters by dividing it by 1000:
Molarity = (0.26 mol) / (300 mL ÷ 1000) = 0.87 M
Therefore, the molarity of the solution is 0.87 M.