Final answer:
The balanced chemical equation for the decomposition of sodium oxide is 2Na2O(s) → 4Na(s) + O2(g). The molar mass of sodium oxide (Na2O) is 45.98 g/mol.
Step-by-step explanation:
a) The balanced chemical equation for the decomposition of sodium oxide is:
2Na2O(s) → 4Na(s) + O2(g)
b) To balance the equation, we need to make sure that the number of each type of atom is the same on both sides of the equation. In this case, there are 2 sodium atoms and 1 oxygen atom on the left side, so we need to adjust the coefficients:
2Na2O(s) → 4Na(s) + O2(g)
c) The molar mass of sodium oxide (Na2O) can be calculated by adding up the atomic masses of sodium (Na) and oxygen (O) in the compound:
Molar mass of Na2O = (2 x atomic mass of Na) + atomic mass of O
= (2 x 22.99 g/mol) + 16.00 g/mol
= 45.98 g/mol
The balanced chemical equation for the decomposition of sodium oxide into sodium and oxygen is 2Na2O(s) → 4Na(s) + O2(g). This equation is balanced with 4 sodium atoms and 2 oxygen atoms on each side. The molar mass of sodium oxide is 61.98 g/mol.
To answer your questions regarding the chemical reaction where sodium oxide decomposes into its elements:
a) Write a chemical equation, predicting the products and including states, to represent this reaction.
The chemical equation for the decomposition of sodium oxide into sodium and oxygen would be:
2Na2O(s) → 4Na(s) + O2(g)
b) Balance the chemical equation.
The chemical equation provided above is already balanced. Each side of the equation has 4 sodium atoms and 2 oxygen atoms.
c) What is the molar mass of sodium oxide?
The molar mass of sodium oxide (Na2O) can be found by adding the molar masses of 2 moles of sodium (Na) to the molar mass of one mole of oxygen (O). The molar mass of sodium is approximately 22.99 g/mol and that of oxygen is approximately 16.00 g/mol. Thus, the molar mass of sodium oxide is:
(2 × 22.99 g/mol) + (16.00 g/mol) = 61.98 g/mol