Final answer:
The heat energy absorbed by 125g of water when its temperature increases by 7.5°C is approximately -3,900 J.
Step-by-step explanation:
To calculate the heat energy absorbed by the water, we can use the equation q = mcΔT, where q is the heat energy, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.
In this case, the mass of the water is 125g and the change in temperature is 7.5°C. The specific heat of water is 4.184 J/(g·°C). Plugging these values into the equation, we get:
q = (125g) * (4.184 J/(g·°C)) * (7.5°C) = -3,909 J ≈ -3,900 J (to 3 significant figures)
Therefore, the correct answer is (d) -3,900 J.