Question

This graph shows the maximum solubility of four different solids, in grams per 100 milliliters of water (g/100 mL). At 60°C, what is the minimum number of grams of KBr that must be added to 100 grams of water to produce a supersaturated solution?

KNO Solubility (g/100 g of water) TKBr Nac
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A) 80 grams
B) 88 grams
C) 90 grams
D) between 88 and 90 grams.

Answer 1

The minimum number of grams of KBr that must be added to 100 grams of water at 60°C to produce a supersaturated solution is 88 grams.

Step-by-step explanation:

The solubility curve shows the maximum solubility of four different solids in grams per 100 milliliters of water (g/100 mL). To find the minimum number of grams of KBr that must be added to 100 grams of water at 60°C to produce a supersaturated solution, we need to locate the solubility of KBr at 60°C on the graph.

Based on the given options (A) 80 grams, (B) 88 grams, (C) 90 grams, and (D) between 88 and 90 grams, we can see that the solubility of KBr at 60°C is around 88 grams per 100 mL. Therefore, the minimum number of grams of KBr that must be added to 100 grams of water at 60°C to produce a supersaturated solution is 88 grams. The correct answer is option (B) 88 grams.