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Consider a gas at sea level occupying a space of 2 liters in a fully elastic balloon at 300 K. If the temperature is increased to 500 K, to what volume would the gas in the balloon expand to? Provide an answer with values to the hundredths place (two spaces past the decimal).

_____ Liters

User Jihoon
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Final answer:

Using Charles's Law, the new volume of the gas at 500 K would be 3.33 liters when initially the gas occupied 2 liters at 300 K.

Step-by-step explanation:

The question is asking to determine the new volume of a gas in a balloon when the temperature is increased from 300 K to 500 K. To solve this problem, we use Charles's Law, which states that for a given mass of an ideal gas at constant pressure, the volume is directly proportional to its temperature in kelvins. Therefore, the formula V1/T1 = V2/T2 can be used, where V1 is the initial volume and T1 is the initial temperature, and V2 and T2 are the final volume and temperature, respectively.



Starting with the values provided, we have V1 = 2 liters and T1 = 300 K. We need to find V2 when T2 = 500 K. Applying Charles's Law:



V2 = (V1 * T2) / T1



V2 = (2 liters * 500 K) / 300 K



V2 = 1000 liters/K / 300 K



V2 = 3.33 liters



Thus, when the temperature is increased to 500 K, the volume of the gas in the balloon will expand to 3.33 liters.

User Pcgilday
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