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3 votes
Solve for x:

A. x = 130
B. x = 120
C. x = 110
D. x = 100

User Vinz
by
7.2k points

2 Answers

2 votes

Final answer:

Without the specific equation to solve, we cannot determine the value of x. Typically, algebraic techniques would be used to isolate and solve for x.

Step-by-step explanation:

The question appears to be a part of a set of problems that require the solving of algebraic equations, specifically in relation to linear equations and perhaps even quadratic equations.

To solve for x, clear steps need to be provided that match the student's course material, which in this case, is missing. Typically, to solve for x, you would isolate the variable x on one side of the equation by performing arithmetic operations such as addition, subtraction, multiplication, or division.

Unfortunately, without the specific equation to solve, we can't determine the correct value of x that corresponds to the options: A. 130, B. 120, C. 110, D. 100.

2 votes

Final answer:

In this case, each student needs to contribute $100 towards the fundraising event,it means that the value of x is 100.

The correct answer is D. x = 100

Step-by-step explanation:

To solve for x in this scenario, we can divide the total amount of money needed ($2000) by the number of students (20) to find the amount each student needs to contribute.

Using the formula:

x = total amount / number of students

We can substitute the values:

x = $2000 / 20

Simplifying the division:

x = $100

Therefore, each student needs to contribute $100 towards the fundraising event.

The correct answer is D, x = 100, which matches the amount calculated through the division.

Your question is incomplete, but most probably the full question was:

You are organizing a fundraising event for your school. There are 20 students in total. You have calculated the total amount of money needed, The total is $2000 , and you know that each student needs to contribute an equal amount (x). Solve for x:

A. x = 130

B. x = 120

C. x = 110

D. x = 100

User Jan Salawa
by
7.5k points