Question

A number plus 10 more than 2 times the number is 43. Find the number.

Answer 1

To find the number, set up an equation x + 10 + 2x = 43. Combine like terms to get 3x + 10 = 43. Solve for x to get x = 11.

Step-by-step explanation:

The student question is asking to solve an algebraic equation. Specifically, a number is to be added to 10 more than twice itself to equal 43. The equation can be written as: x + 10 + 2x = 43, where x represents the unknown number.

To find the number, combine like terms and solve for x:

1. Combine like terms: 1x + 2x = 3x, so the equation becomes 3x + 10 = 43.
2. Subtract 10 from both sides: 3x = 43 - 10, which simplifies to 3x = 33.
3. Divide both sides by 3: x = 33 / 3, so the number x = 11.

Therefore, the number is 11.