Question

3.What are the forces (in N) on two charges of +0.800 C and −5.00 C, respectively, if they are separated by a distance of 5.00 m?magnitude answer in:_____Nwill it: attract or repel?

Answer 1

Given:

The charge q1 = 0.8 C

The charge q2 = -5 C

The distance between the charges is r = 5 m

Required: The magnitude of force and type of force (attraction/repulsion)

Step-by-step explanation:

The magnitude of the force can be calculated by Coulomb's law

`F=k(|q1q2|)/(r^2)`

Here, k is the electrostatic constant whose value is

`k=9*10^9\text{ Nm}^2\text{ /C}^2`

On substituting the values, the magnitude of force will be

`\begin{gathered} F=9*10^9*(0.8*5)/((5)^2) \\ =1.44*10^9\text{ N} \end{gathered}`

The charges are opposite in nature, thus the charges will attract.

Final Answer: The magnitude of the force is 1.44e9 N and the charges will attract.