Final answer:
To solve for x and y in the simultaneous equations x squared + y squared = 1 and x + 2y = 1, we isolate x in the second equation and substitute it into the first equation. This leads to two possible solutions for y, which then give us two corresponding x values, resulting in two solution pairs for the equations.
Step-by-step explanation:
To solve these simultaneous equations, we need to find values of x and y that satisfy both equations:
- x squared + y squared = 1
- x + 2y = 1
Let's solve the second equation for x:
x = 1 - 2y
Now, substitute this x value into the first equation:
(1 - 2y)2 + y2 = 1
Expand and simplify:
1 - 4y + 4y2 + y2 = 1
Combine like terms and move all terms to one side:
5y2 - 4y = 0
Factoring out y:
y(5y - 4) = 0
This gives two possible values for y:
- y = 0
- y = 4/5
For y = 0, substituting back into x + 2y = 1:
x = 1
For y = 4/5, substituting back into x + 2y = 1:
x = 1 - 2(4/5)
x = 1 - 8/5
x = -3/5
The solutions to the simultaneous equations are (1, 0) and (-3/5, 4/5).