Final answer:
The final pressure of the gas will be approximately 537.78 mm Hg.
To determine the final pressure of the gas when its temperature is lowered to 15.0°C and its volume increases to 90.0 L, the combined gas law is used. The final pressure calculated is 490.5 mm Hg.
Step-by-step explanation:
To find the final pressure of the gas, we can use the combined gas law, which states that for a given amount of gas at constant temperature, the product of the initial pressure and volume is equal to the product of the final pressure and volume.
Using this formula, we can calculate the final pressure:
P1*V1 = P2*V2
Plugging in the given values:
690. mm Hg * 70.0 L = P2 * 90.0 L
Solving for P2:
P2 = (690. mm Hg * 70.0 L) / 90.0 L = 537.78 mm Hg
Therefore, the final pressure of the gas will be approximately 537.78 mm Hg.
To determine the final pressure of the gas when its temperature is lowered to 15.0°C and its volume increases to 90.0 L, the combined gas law is used. The final pressure calculated is 490.5 mm Hg.
The question entails finding the final pressure of a gas after a change in temperature and volume occurs, based on the initial conditions of 690 mm Hg, 70.0 L, and 20.0°C.
To solve this, we can use the combined gas law, which is P1*V1/T1 = P2*V2/T2, where 'P' denotes pressure, 'V' is volume, and 'T' is temperature in Kelvin. First, we should convert all our temperatures to Kelvin by adding 273.15 to the Celsius temperatures. This gives us initial and final temperatures of T1 = 293.15 K and T2 = 288.15 K respectively.
Next, we plug in the known values:
690 mm Hg * 70.0 L / 293.15 K = P2 * 90.0 L / 288.15 K
By solving for P2:
P2 = (690 mm Hg * 70.0 L / 293.15 K) * (288.15 K / 90.0 L) = 490.5 mm Hg