Question

For 7x + 35 and the multiplicative inverse of 7, write the product and then write the expression in standard form, if possible.

Answer 1

To find the product of 7x and the multiplicative inverse of 7, multiply the two expressions together. The expression in standard form is x.

Step-by-step explanation:

To find the product of 7x and the multiplicative inverse of 7, we need to multiply the two expressions together. The multiplicative inverse of 7 is 1/7, so the product is (7x)(1/7) = x.

To write the expression in standard form, we simply rewrite it as x.

Answer 2

`\[ 7x + 35 \ \text{multiplied by} \ (1)/(7) = x + 5 \]`

Step-by-step explanation:

To find the product of \(7x + 35\) and its multiplicative inverse
`\((1)/(7)\)`, we simply multiply the expression by the reciprocal of the coefficient of \(x\), which is
`\((1)/(7)\)`. The product is \(x + 5\).

The expression \(x + 5\) is already in standard form, where the term with the highest power of \(x\) comes first, followed by lower-degree terms and constants. Therefore, \(x + 5\) is in standard form.

Understanding how to find the multiplicative inverse of a coefficient and how to express an algebraic expression in standard form is fundamental in algebra, providing the basis for various manipulations and simplifications.