Question

An air bubble has a volume of 0.500 L at 18 °C. What is the final volume, in L of the gas when the temperature changes to -12°C, if the pressure and amount of gas do not change?

a) 0.363 L
b) 0.490 L
c) 0.448 L
d) 0.557 L

Answer 1

Using Charles's Law, the final volume of the air bubble when the temperature changes to -12°C, while keeping the pressure and amount of gas constant, is calculated to be 0.448 L.

Step-by-step explanation:

To find the final volume of the gas when temperature changes, we can use the Charles's Law, which states that at constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature (measured in Kelvin). The formula for Charles's Law is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

The initial volume (V1) is 0.500 L and the initial temperature (T1) is 18 °C, which is 291 K (since temperature in Kelvin = temperature in °C + 273.15). The final temperature (T2) is -12 °C or 261 K. Rearranging Charles's Law formula to solve for V2 gives us V2 = V1 * (T2/T1).

Plugging in the values, we have V2 = 0.500 L * (261 K / 291 K) = 0.448 L. Therefore, the final volume of the gas at -12 °C, when the pressure and amount of gas do not change, is 0.448 L.