Question

Directions: Find the x and y intercepts for each equation.

1.) y = x^2 - 1211
2.) y = x^2 - 1
3.) y = x^2 - 81
4.) y = x^2 - 100
5.) y = x^2 - 144
6.) y = x^2 - 36
7.) y = x^2 - 400
8.) y = x^2 - 900

Answer 1

To find the x and y intercepts of each quadratic equation, set y to zero and solve for x to find the x-intercepts, and set x to zero to find the y-intercepts. The y-intercept of each equation is simply (0, c) where c is the constant term in the equation, and the x-intercepts are found by solving x^2 = c.

Step-by-step explanation:

To find the x-intercepts and y-intercepts of each equation, we set y to 0 to find the x-intercepts and set x to 0 to find the y-intercepts.

1. y = x^2 - 121: The y-intercept is (0, -121) since that's where x is 0. The x-intercepts are where y=0, so solve x^2 - 121 = 0, which gives us x = ±11.
2. y = x^2 - 1: The y-intercept is (0, -1). The x-intercepts are found by setting the equation to 0: x^2 - 1 = 0, which results in x = ±1.
3. y = x^2 - 8: The y-intercept is (0, -8). For the x-intercepts solve x^2 - 8 = 0, giving us x = ±2√2.
4. Following the same method, you can find the intercepts for the remaining equations: y = x^2 - 100, y = x^2 - 144, y = x^2 - 36, y = x^2 - 400, and y = x^2 - 900.